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(Stranger )
07/26/08 12:33 AM
to solve differential equations in verilog-a? Report this article as Inappropriate to us !!!Login to Reply

   Now I'm using verilog-a to do some research on modeling kinematic structures. We all know that ddt or idt is accepted in verilog-a, such like the following sentences:

  But if Fdrv is from a source outside my module and i want to output the x in the following differential equation, how can i?


   i've written these codes,
   module test(Fdrv,x);
       inout Fdrv,x;
       kinematic Fdrv,x;
       kinematic v; //temp. var. to hold ddt(x)
       parameter real a=xxx, b=xxx, c=xxx; // assume a,b,c are properly defined      
               analog begin

    if i input x to module test, i will get proper output of Fdrv, but if i want to input Fdrv and get the
proper value of x, which means i want to solve this differential equation, it never works.
    How can i solve this problem? thank you very very much....

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